![]() ![]() ![]() So, the ending message implies that Sam is still out there, making the world a better place. Samuel 'Sam' Beckett invented a theory about time traveling and led a group of scientists to the desert to develop a top-secret. The part of Sam is played by actor Scott Bakula. and immediately after, the screen fades to black, displaying a text note stating that Sam never returned home. Earlier in that same episode, Sam had been told that he'd always had the power to stop leaping, but his subconscious continues to want to put things right. Samuel 'Sam' John Beckett is the main scientist behind the Project Quantum Leap on the TV series Quantum Leap. Sam Beckett stepped into the Quantum Leap accelerator and vanished. In the unsatisfying final episode of the fifth season, "Mirror Image," which turned out to be the series finale, Sam makes a "final" leap to change history and fix the most painful event of Al's life. According to the synopsis for this potential new Quantum Leap: It’s been 30 years since Dr. Sam Beckett (played in the original series by Scott Bakula) stepped into the Quantum Leap accelerator. ![]() Meanwhile, Sam - aided by the holographic image of his friend, Al Calavicci's (Dean Stockwell) – slowly pieces together his own identity, which he's forgotten due to the effects of time travel. 19 at 10/9c on NBC, the reboot takes place 30 years after Dr. Sam Beckett ( Scott Bakula) closed on a fizzling cliffhanger in Mirror Image, the 1993 series finale that dashed out a hasty explanation for all those lingering, leapin’ loose ends. The five-season series followed Sam, a physicist, who - after being on the verge of losing funding for his time travel project - steps into his own project accelerator, whereupon he finds himself, as the intro states, "leaping from life to life, striving to put right what once went wrong - and hoping each time that his next leap will be the leap home." This meant every episode took place in a different year and genre, with Sam helping people and saving lives in the past. ![]()
0 Comments
Leave a Reply. |